MESSAGE
DATE | 2017-03-20 |
FROM | Ruben Safir
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SUBJECT | Subject: [Learn] hough transform - Lecture 9
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From learn-bounces-at-nylxs.com Mon Mar 20 17:43:14 2017 Return-Path: X-Original-To: archive-at-mrbrklyn.com Delivered-To: archive-at-mrbrklyn.com Received: from www.mrbrklyn.com (www.mrbrklyn.com [96.57.23.82]) by mrbrklyn.com (Postfix) with ESMTP id A7261161312; Mon, 20 Mar 2017 17:43:14 -0400 (EDT) X-Original-To: learn-at-nylxs.com Delivered-To: learn-at-nylxs.com Received: from mailbackend.panix.com (mailbackend.panix.com [166.84.1.89]) by mrbrklyn.com (Postfix) with ESMTP id B726C160E77 for ; Mon, 20 Mar 2017 17:43:11 -0400 (EDT) Received: from [172.22.144.177] (182631b.cst.lightpath.net [24.38.3.27]) by mailbackend.panix.com (Postfix) with ESMTPSA id 9E37B1FA29; Mon, 20 Mar 2017 17:43:10 -0400 (EDT) To: herrc-at-rit.edu, rhody-at-cis.rit.edu, learn-at-nylxs.com From: Ruben Safir Message-ID: <58D04CEE.4030903-at-panix.com> Date: Mon, 20 Mar 2017 17:43:10 -0400 User-Agent: Mozilla/5.0 (X11; Linux x86_64; rv:38.0) Gecko/20100101 Icedove/38.8.0 MIME-Version: 1.0 Subject: [Learn] hough transform - Lecture 9 X-BeenThere: learn-at-nylxs.com X-Mailman-Version: 2.1.17 Precedence: list List-Id: List-Unsubscribe: , List-Archive: List-Post: List-Help: List-Subscribe: , Content-Transfer-Encoding: quoted-printable Content-Type: text/plain; charset="utf-8"; Format="flowed" Errors-To: learn-bounces-at-nylxs.com Sender: "Learn"
Good afternoom Dr Rhody
I have been studying your wonderful notes on the Hough Transform. They =
are the best review of this material that I've seen, but there is one =
area that has me befuddled. Perhaps there is an error in this part of =
the notes. specifically I am referring to the 9th lecture notes
https://www.cis.rit.edu/class/simg782/lectures/lecture_09/lec782_05_09.pdf
Create a set of counters, one for each parameter pair, initialized to zero. For each point (x n , y n ) For each a i compute b =3D =E2=88=92a i x n + y n Find the point (a i , b j ) closest to (a i , b) Increment counter for (a i , b j )
I'm struggling to understand how this can work. Once we have a valid =
a,b then we need increment it and walk to the next x,y . After all the =
X,Y's are covered, the a,b with the largest incremented value is the =
valid line(s)
Please let me know how I am wrong in this
Sincerely Ruben Safir MS Comp Sci (candidate 2017)
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