MESSAGE
DATE | 2014-12-06 |
FROM | Ruben Safir
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SUBJECT | Re: [LIU Comp Sci] Parity Bit Algebra
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From owner-learn-outgoing-at-mrbrklyn.com Sat Dec 6 21:36:08 2014 Return-Path: X-Original-To: archive-at-mrbrklyn.com Delivered-To: archive-at-mrbrklyn.com Received: by mrbrklyn.com (Postfix) id 02E9816007B; Sat, 6 Dec 2014 21:36:08 -0500 (EST) Delivered-To: learn-outgoing-at-mrbrklyn.com Received: by mrbrklyn.com (Postfix, from userid 28) id DD61616112F; Sat, 6 Dec 2014 21:36:07 -0500 (EST) Delivered-To: learn-at-mrbrklyn.com Received: from mailbackend.panix.com (mailbackend.panix.com [166.84.1.89]) by mrbrklyn.com (Postfix) with ESMTP id EB44D16007B for ; Sat, 6 Dec 2014 21:36:06 -0500 (EST) Received: from [10.0.0.42] (unknown [96.57.23.82]) by mailbackend.panix.com (Postfix) with ESMTPSA id BFE6013E29 for ; Sat, 6 Dec 2014 21:36:06 -0500 (EST) Message-ID: <5483BD3C.9020609-at-panix.com> Date: Sun, 07 Dec 2014 02:36:44 +0000 From: Ruben Safir User-Agent: Mozilla/5.0 (X11; Linux x86_64; rv:31.0) Gecko/20100101 Thunderbird/31.2.0 MIME-Version: 1.0 To: learn-at-mrbrklyn.com Subject: Re: [LIU Comp Sci] Parity Bit Algebra References: <54838832.6010205-at-panix.com> <54838C85.60705-at-panix.com> In-Reply-To: Content-Type: text/plain; charset=utf-8 Content-Transfer-Encoding: 7bit Sender: owner-learn-at-mrbrklyn.com Precedence: bulk Reply-To: learn-at-mrbrklyn.com
On 12/06/2014 11:09 PM, Maneesh Kongara wrote: > Preliminary work as in answers to the other questions of the assignment? > On Dec 6, 2014 6:08 PM, "Ruben Safir" wrote:
I'm going to crash, how far did you get in the assingment.
Call me is 20 minutes. I have one hour to do it :)
>> On 12/06/2014 10:52 PM, Maneesh Kongara wrote: >>> Thanks so much for sharing Mr Rubin. Have you completed the assignment? >>> On Dec 6, 2014 5:49 PM, "Ruben Safir" wrote: >> Not even looked at it outside of the library. I'm burning up trying to >> catch up. Do you have some preliminary work? >> >> I did give it throught. Part of the solution must have to do with the >> Comp + 2 binary >> >> I can't even find my notes... >> >>>> This is from theidiscussion of Raid 3 Stallings Text which the slide >>>> come from. It is related to the problem you asked about the parity bit >>>> calculation for the Hamming Code >>>> >>>> Not the methodology for logical calculation, it is straight math >>>> >>>> Note that X is XOR for whatever UFT reason >>>> >>>> >>>> REDUNDANCY In the event of a drive failure, the parity drive is accessed >>>> and data is reconstructed from the remaining devices. Once the failed >>>> drive is replaced, the missing data can be restored on the new drive and >>>> operation resumed. >>>> >>>> Data reconstruction is simple. Consider an array of five drives in which >>>> X0 through X3 contain data and X4 is the parity disk.The parity for the >>>> ith bit is calculated as follows: >>>> >>>> X4(i) = X3(i) { X2(i) { X1(i) { X0(i) >>>> >>>> where { is exclusive-OR function. >>>> >>>> Suppose that drive X1 has failed. If we add X4(i) { X1(i) to both sides >>>> of the preceding equation, we get >>>> >>>> X1(i) = X4(i) { X3(i) { X2(i) { X0(i) >>>> >>>> >>>> file:///home/ruben/william stallings - computer organization and >>>> architecture designing for performance (8th edition).pdf >>>> >>>> Page 202 >>>> >>>> >>>> >>>> http://www.nylxs.com/images/raid3_parity_math.png >>>> >>>> Ruben >>>> >>
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