MESSAGE
DATE | 2014-12-06 |
FROM | Ruben Safir
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SUBJECT | Re: [LIU Comp Sci] Parity Bit Algebra
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From owner-learn-outgoing-at-mrbrklyn.com Sat Dec 6 18:08:13 2014 Return-Path: X-Original-To: archive-at-mrbrklyn.com Delivered-To: archive-at-mrbrklyn.com Received: by mrbrklyn.com (Postfix) id 2B31916007B; Sat, 6 Dec 2014 18:08:13 -0500 (EST) Delivered-To: learn-outgoing-at-mrbrklyn.com Received: by mrbrklyn.com (Postfix, from userid 28) id 1436F16112F; Sat, 6 Dec 2014 18:08:13 -0500 (EST) Delivered-To: learn-at-mrbrklyn.com Received: from mailbackend.panix.com (mailbackend.panix.com [166.84.1.89]) by mrbrklyn.com (Postfix) with ESMTP id 021D116007B for ; Sat, 6 Dec 2014 18:08:11 -0500 (EST) Received: from [10.0.0.42] (unknown [96.57.23.82]) by mailbackend.panix.com (Postfix) with ESMTPSA id B9DE813961 for ; Sat, 6 Dec 2014 18:08:10 -0500 (EST) Message-ID: <54838C85.60705-at-panix.com> Date: Sat, 06 Dec 2014 23:08:53 +0000 From: Ruben Safir User-Agent: Mozilla/5.0 (X11; Linux x86_64; rv:31.0) Gecko/20100101 Thunderbird/31.2.0 MIME-Version: 1.0 To: learn-at-mrbrklyn.com Subject: Re: [LIU Comp Sci] Parity Bit Algebra References: <54838832.6010205-at-panix.com> In-Reply-To: Content-Type: text/plain; charset=utf-8 Content-Transfer-Encoding: 7bit Sender: owner-learn-at-mrbrklyn.com Precedence: bulk Reply-To: learn-at-mrbrklyn.com
On 12/06/2014 10:52 PM, Maneesh Kongara wrote: > Thanks so much for sharing Mr Rubin. Have you completed the assignment? > On Dec 6, 2014 5:49 PM, "Ruben Safir" wrote:
Not even looked at it outside of the library. I'm burning up trying to catch up. Do you have some preliminary work?
I did give it throught. Part of the solution must have to do with the Comp + 2 binary
I can't even find my notes...
>> This is from theidiscussion of Raid 3 Stallings Text which the slide >> come from. It is related to the problem you asked about the parity bit >> calculation for the Hamming Code >> >> Not the methodology for logical calculation, it is straight math >> >> Note that X is XOR for whatever UFT reason >> >> >> REDUNDANCY In the event of a drive failure, the parity drive is accessed >> and data is reconstructed from the remaining devices. Once the failed >> drive is replaced, the missing data can be restored on the new drive and >> operation resumed. >> >> Data reconstruction is simple. Consider an array of five drives in which >> X0 through X3 contain data and X4 is the parity disk.The parity for the >> ith bit is calculated as follows: >> >> X4(i) = X3(i) { X2(i) { X1(i) { X0(i) >> >> where { is exclusive-OR function. >> >> Suppose that drive X1 has failed. If we add X4(i) { X1(i) to both sides >> of the preceding equation, we get >> >> X1(i) = X4(i) { X3(i) { X2(i) { X0(i) >> >> >> file:///home/ruben/william stallings - computer organization and >> architecture designing for performance (8th edition).pdf >> >> Page 202 >> >> >> >> http://www.nylxs.com/images/raid3_parity_math.png >> >> Ruben >>
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