MESSAGE
| DATE | 2016-01-27 |
| FROM | Ruben Safir
|
| SUBJECT | Subject: [Hangout-NYLXS] Lexical issues in C++
|
Check this out, it might be useful
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NNTP-Posting-Date: Thu, 24 Dec 2015 17:34:24 -0600
Newsgroups: comp.lang.c++
Subject: Re: Converting from int* to char*
From: Paavo Helde
References: <0be9ea2b-738b-419f-8d1f-fc1ea862dbde-at-googlegroups.com>
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Xref: panix comp.lang.c++:1118257
Paul wrote in
news:0be9ea2b-738b-419f-8d1f-fc1ea862dbde-at-googlegroups.com:
> I'm confused about when conversions between types are allowed.
> int* z = new int(3);
> char* x= (char*)z; //works fine.
>
> However, if the second line is replaced by char* x = char*(z); I get
> "expected primary expression before char" compile error. I was
> anticipating that I can cast from int* to char* this way in the same way
> that you can cast 5.3 to int by writing int(5.3);
This is a lexical issue, it just does not make sense to multiply a type
char with something. Change it to
char* x = reinterpret_cast(z);
or
char* x = (char*)(z);
or
typedef char* charPtr;
charPtr x = charPtr(z);
Note that only the first one is really C++.
> If the second line is replaced by char*x = z; I get an error -- "can not
> convert from char* to int* in initialization" How could I have know
> that such an initialization is illegal, given that the cast of the form
> char* x = (char*)z; is ok ?
By reading and understanding the language rules?
hth Paavo
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