MESSAGE
| DATE | 2005-01-26 |
| FROM | Billy
|
| SUBJECT | Re: [hangout] Simple C question
|
Ruben Safir wrote:
> On Tue, 2005-01-25 at 16:03, Billy wrote:
>
>>Inker, Evan wrote:
>>>
>>>#include
>>>#include
>>>
>>>void strcopy(const char *, char *);
>>>
>>>int main() {
>>> char string1[] = "This is string1";
>>> char string2[] = "This is string2";
>>>
>>> strcopy(string1, string2);
>>> printf("String2: %s", string2);
>>>}
>>>
>>>void strcopy(const char * str1, char * str2) {
>>> int x = 0;
>>>
>>> /* change the size of string2 to the size of string1 */
>>> realloc(str2, sizeof(str1));
>>>
>>> do {
>>> str2[x] = str1[x];
>>> } while (str1[x++] != '\0');
>>>
>>>}
>>
>>
>>This program is incorrect.
>>YOU CANNOT overwrite the contents of string2.
>
>
>
> Why not? It is not a string literal.
char string2[] = "This is string2";
Yes it is.
>
>> It is also illegal to
>>realloc() a pointer which was not obtained by malloc().
>>also, realloc is free to move the block. you have to use its return
>>value to update the pointer. There's just so much wrong...
>>
>>I DON'T RECOMMEND learning from this example.
>>
>
>
> I agree. There is no reason to rewrite strncpy
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