MESSAGE
| DATE | 2002-04-24 |
| FROM | Ruben I Safir
|
| SUBJECT | Re: [hangout] C problem
|
Yes
That's right, but it still doesn't work and I'm not
sure why. When you send CTL D the scanf returns a -1, which I asume is the
EOF result, and the if statement doesn't break.
This is why I use Perl
Ruben
> Wow. I feel really stupid. I don't know how that happened. I guess I
> was looking at the warnings.
>
> I think that the problem is one of operator precedence. try:
> if (!(ret=scanf("%255s", buff_key)))
>
> I just tested the two lines
> z = (!y=x);
>
> and
> z = (!(y=x));
>
> The latter works but not the former. The first is trying to assign the
> value x to !y
>
> On Wed, 24 Apr 2002 01:20:19 -0400 (EDT)
> Ruben I Safir wrote:
>
> >
> > > First, what is g_hash_table_new(), if those warnings are important
> > > to you?
> > >
> >
> > ITs a gtk function which has nothing to do with the problem
> >
> >
> > > Second, hTable must be declared
> >
> >
> > Yahah yadah - it's declared above main where it belongs
> >
> > The error is the lvalue
> > int ret and scanf
> >
> > THIS is the line which is the problem
> >
> > > > if(! ret=scanf("%255s", buff_key)) break; <====LINE 35
> > > > hash.c:35: invalid
> > > > lvalue in assignment
> > > >
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>
____________________________
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Fair Use -
because it's either fair use or useless....
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